From: Pierre.Boulet@lifl.fr (Pierre.Boulet)
To: John Erickson <jderick@cs.utexas.edu>
Cc: caml-list@inria.fr
Subject: Re: [Caml-list] copying Streams
Date: 10 Jul 2001 11:03:22 +0200 [thread overview]
Message-ID: <vtu1ynp6tr9.fsf@gala.lifl.fr> (raw)
In-Reply-To: John Erickson's message of "Mon, 9 Jul 2001 22:44:16 -0500"
> Is there any way to copy a Stream (from the standard library)
> in such a way that the original stream is not modified when the
> copy is used and vice versa?
I have not managed yet to do what you want but I may have a
workaround: here is a function that builds two streams from another
one such that the two produced streams work together to only remove
elements form the source stream when both have read it. They thus
appear as two independent streams containing the same elements.
let stream_get_nth n s =
let i = (n+1)-(Stream.count s) in
try List.nth (Stream.npeek i s) (i-1)
with Failure "nth" -> raise Stream.Failure
let stream_duplicate s =
let start_count = Stream.count s in
let count1 = ref start_count
and count2 = ref start_count in
let get c1 c2 n =
let n' = n + start_count in
if n' < !c1 then raise Stream.Failure
else begin
incr c1;
if n' >= !c2
then
try Some (stream_get_nth n' s)
with Stream.Failure -> None
else
try Some (Stream.next s)
with Stream.Failure -> None
end in
let get1 n = get count1 count2 n
and get2 n = get count2 count1 n
in
(Stream.from get1), (Stream.from get2)
--
Pierre.Boulet@lifl.fr - http://www.lifl.fr/~boulet
In theory, practice and theory are the same,
but in practice they are different. -- Larry McVoy
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prev parent reply other threads:[~2001-07-10 9:03 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2001-07-10 3:44 John Erickson
2001-07-10 8:44 ` Daniel de Rauglaudre
2001-07-10 9:03 ` Pierre.Boulet [this message]
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