From: "Jonathan Roewen" <jonathan.roewen@gmail.com>
To: OCaml <caml-list@yquem.inria.fr>
Subject: [Caml-list] Trying to understand recursion curiosity
Date: Fri, 31 Mar 2006 15:00:49 +1200 [thread overview]
Message-ID: <ad8cfe7e0603301900p461a05c5xb3961b11f98c2910@mail.gmail.com> (raw)
Hi,
I have some code for implementing some parser combinators, and have
stumbled upon some unexpected behaviour in my definition of a
combinator that's recursive.
Here's the definitions:
> (* some parsers *)
> let x = literal "x"
> let s = literal ","
> (* initial definition *)
> let rec one_or_more_with_sep pa ps =
> try_with
> (then3 (fun x y z -> x :: z) pa ps (one_or_more_with_sep pa ps))
> (pa --> (fun x -> [x]))
> (* try to define a parser *)
> let xs = one_or_more_with_sep x s
Stack overflow during evaluation (looping recursion?).
> (* new definition *)
> let rec one_or_more_with_sep pa ps = fun ts ->
> try_with
> (then3 (fun x y z -> x :: z) pa ps (one_or_more_with_sep pa ps))
> (pa --> (fun x -> [x]))
> ts
> (* try to define a parser with amended definition *)
> let xs = one_or_more_with_sep x s
val xs : string list -> (string list * string list) list = <fun>
I've omitted the definitions of try_with, then3, and apply (-->).
try_with tries the first parser, and if it returns the empty list,
uses the second.
BTW: a parser returns a list of possible parses.
Kindest Regards,
Jonathan Roewen
reply other threads:[~2006-03-31 3:00 UTC|newest]
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