* Re: [Caml-list] New to OCaml: can someone explain how this code can be done better?
@ 2001-06-24 6:03 Jeremy Fincher
0 siblings, 0 replies; 5+ messages in thread
From: Jeremy Fincher @ 2001-06-24 6:03 UTC (permalink / raw)
To: caml-list
Thanks! Going through and understanding your code helped me a lot, and was
a terrific aid in seeing the functional (rather than imperative) way of
looping. One question, though:
> let explode string =
> let rec loop i acc =
> if i = 0 then acc
> else let i' = i-1 in loop i' (string.[i'] :: acc)
> in
> loop (String.length string) []
Could this be rewritten as this, to remove the if/else? --
let explode string =
let rec loop acc = function
| 0 -> acc
| i -> loop (string.[i-1] :: acc) (i-1)
in
loop [] (String.length string)
Thanks for your excellent examples.
Jeremy
>
> let implode list =
> let string = String.create (List.length list) in
> let rec loop i = function
> | x :: rest -> string.[i] <- x; loop (i+1) rest
> | [] -> ()
> in
> loop 0 list;
> string
>
> let permute_string s =
> List.map implode (permute (explode s))
>
>(* Eric Cooper, ecc@cmu.edu *)
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* Re: [Caml-list] New to OCaml: can someone explain how this code can be done better?
@ 2001-06-24 5:49 Jeremy Fincher
0 siblings, 0 replies; 5+ messages in thread
From: Jeremy Fincher @ 2001-06-24 5:49 UTC (permalink / raw)
To: caml-list
>The function permute_rec is an implementation detail.
>So you scope it _inside_ the permute function
I was worried this would incur a slow down (in Python, nested function
objects are instantiated when a function is called and destroyed when it
exits; the code object isn't destroyed, but there still is the additional
overhead of creating a function object from it.) I assume now, since it's a
feature so widely used (I see it anytime I look at others' OCaml code) that
it doesn't. Thanks for pointing that out.
Jeremy
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* [Caml-list] New to OCaml: can someone explain how this code can be done better?
@ 2001-06-23 5:27 Jeremy Fincher
2001-06-23 19:39 ` Eric C. Cooper
0 siblings, 1 reply; 5+ messages in thread
From: Jeremy Fincher @ 2001-06-23 5:27 UTC (permalink / raw)
To: caml-list
Since I'm learning OCaml, I've been writing little functions as I get a
grasp on each little bit of the syntax. One of these functions is
"permute", which takes a string and returns a list of all the permutations
of the string. Here's the function:
let rec permute_rec f s =
if String.length s = 1 then
(f ^ s) :: []
else
let l = ref [] in
for i = 0 to ((String.length s) - 1) do
let c = String.sub s i 1 in
let rem = (String.sub s 0 i) ^ ((String.sub s (i+1) ((String.length
s)-i-1))) in
l := (List.append !l (permute_rec (f^c) rem))
done;
!l;;
let permute = permute_rec "";;
Now, I'm sure this isn't the best way to code that function. What I'm
hoping is that someone can show me a few things about the function: how to
make it tail recursive; a better (less imperative?) method of writing it,
and which parts are not consistent with common/standard OCaml idiom.
*Anything* I'm shown should at least help me learn, so if you have any
comments/opinions, please tell me!
Thanks,
Jeremy
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* Re: [Caml-list] New to OCaml: can someone explain how this code can be done better?
2001-06-23 5:27 Jeremy Fincher
@ 2001-06-23 19:39 ` Eric C. Cooper
2001-06-25 18:40 ` Stefano Zacchiroli
0 siblings, 1 reply; 5+ messages in thread
From: Eric C. Cooper @ 2001-06-23 19:39 UTC (permalink / raw)
To: caml-list
(* Here is one approach to the problem.
I think it is more natural to define permute on lists,
and then write permute_string by converting to and from lists of
characters. As you'll see, the only imperative code is in this
conversion step; the rest is purely functional.
A simple recursive definition of permute is the following:
The only permutation of an empty list is the empty list.
Otherwise, the permutations of [x1;...;xN] are obtained by
inserting x1 at all possible positions in each of
the permutations of [x2;...;xN].
We can translate this directly into ML: *)
(* (distribute e [x1;...;xN]) returns the list
[ [e;x1;...;xN]; [x1;e;x2;...;xN]; ...; [x1;...;xN;e] ] *)
let rec distribute elt = function
| (hd :: tl) as list ->
(elt :: list) :: (List.map (fun x -> hd :: x) (distribute elt
tl))
| [] -> [ [elt] ]
(* (permute [x1;...;xN] returns the list of all permutations
of [x1;...;xN] *)
let rec permute = function
| x :: rest -> List.flatten (List.map (distribute x) (permute
rest))
| [] -> [ [] ]
(* Since we probably don't care about the order of the list of
permutations, we can be slightly more efficient by defining a
tail-recursive combination of flatten and map: *)
(* (flat_rev_map f [x1;...;xN]) returns the list
[rev (f xN) @ ... @ rev (f x1)] *)
let flat_rev_map f list =
let rec loop acc = function
| x :: rest -> loop (List.rev_append (f x) acc) rest
| [] -> acc
in
loop [] list
let rec permute = function
| x :: rest -> flat_rev_map (distribute x) (permute rest)
| [] -> [ [] ]
(* Finally, we convert to and from strings using
implode and explode functions: *)
let explode string =
let rec loop i acc =
if i = 0 then acc
else let i' = i-1 in loop i' (string.[i'] :: acc)
in
loop (String.length string) []
let implode list =
let string = String.create (List.length list) in
let rec loop i = function
| x :: rest -> string.[i] <- x; loop (i+1) rest
| [] -> ()
in
loop 0 list;
string
let permute_string s =
List.map implode (permute (explode s))
(* Eric Cooper, ecc@cmu.edu *)
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