From: Diego Olivier Fernandez Pons <dofp.ocaml@gmail.com>
To: Ly Kim Quyen <lykimq@gmail.com>
Cc: caml-list@inria.fr
Subject: Re: [Caml-list] Compute the equivalence classes
Date: Tue, 1 Nov 2011 18:55:24 +0100 [thread overview]
Message-ID: <CAHqiZ-Jg36Tu-4zgXe9M1dUMqQQ-NJwjKt2LO0Oo-N_EFc4-+w@mail.gmail.com> (raw)
In-Reply-To: <CAHqiZ-+T=7nep4TmUuzzYu0qMpO908TmegwaNCg7f--+4PVeGw@mail.gmail.com>
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... sorry, sent too early
> You can compute the strongly connected components directly on the
transitive closure. Notice you don't need to transpose it explicitely
// Strong connected components matrix form
let sccmatrix = function matrix ->
let n = Array.length matrix in
let result = Array.make_matrix n n 0 in
for i = 0 to n - 1 do
for j = 0 to n - 1 do
result.(i).(j) <- min matrix.(i).(j) matrix.(j).(i)
done;
done;
result
Now you just have to collect the results in a list of lists.
You will need to avoid generating multiple times the same component.
// Output list of lists from matrix
let output = function matrix ->
let n = Array.length matrix in
let marked = Array.make n false in
let result = ref [] in
for i = 0 to n - 1 do
if (not marked.(i)) then
begin
let component = ref [i] in
for j = i + 1 to n - 1 do
if matrix.(i).(j) = 1 then
begin
marked.(j) <- true;
component := j :: !component
end
done;
result := !component :: !result
end
done;
!result
Since the code uses for loops, it needs references to store the results.
One can do a nicer code and merge the two functions sccmatrix and output
Diego Olivier
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next prev parent reply other threads:[~2011-11-01 17:55 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2011-10-31 15:36 Ly Kim Quyen
2011-10-31 16:13 ` Kakadu
2011-10-31 23:59 ` Toby Kelsey
2011-11-01 17:20 ` Diego Olivier Fernandez Pons
2011-11-01 17:55 ` Diego Olivier Fernandez Pons [this message]
2011-11-03 8:10 ` Ly Kim Quyen
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