Re: [Caml-list] How to get the path of Filename.current_dir_name

[Pierrick Couderc <pierrickcouderc@gmail.com>]

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>
>  __FILE__ returns the name of the module, not the name and absolute path.


Actually, it returns the exact path given to the compiler. For example :
  $ cd /tmp
  $ echo 'Printf.printf \"File path: %s\n%!" __FILE__;;' > t.ml

Then compiled and executed:
  $ ocamlc t.ml && ./a.out
  > File path: t.ml

  $ ocamlc /tmp/t.ml && ./a.out
  > File path: /tmp/t.ml

  $ ocamlc ../tmp/../tmp/t.ml && ./a.out
  > File path: ../tmp/../tmp/t.ml

2016-10-10 10:47 GMT+02:00 Gustave Nimant <gustave.nimant@free.fr>:

> On 05/10/2016 16:34, Pierrick Couderc wrote:
>
>
> If I understood correctly, it is more about the directory of the module at
> compile time.
>
> the absolute path of the module at compile time.
>
> One (hackish) way to do it is with the value __FILE__  in Pervasives (see
> http://caml.inria.fr/pub/docs/manual-ocaml/libref/
> Pervasives.html#6_Debugging for some compile time constant used for
> debugging).
> It simply returns the path of the .ml given to the compiler, not an
> absolute path (except if you called the compiler on an absolute path, of
> course).
>
>  __FILE__ returns the name of the module, not the name and absolute path.
> I do not understand what do you mean by "except if you called the compiler
> on an absolute path, of course"
> could you please give me more details about calling the compiler on an
> absolute path ?
>
> Thanks
> Gustave
>

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