* Unusual type declaration and Sexplib
@ 2009-02-22 20:59 Dario Teixeira
2009-02-23 10:27 ` [Caml-list] " Jacques Garrigue
0 siblings, 1 reply; 3+ messages in thread
From: Dario Teixeira @ 2009-02-22 20:59 UTC (permalink / raw)
To: caml-list
Hi,
I'm having some trouble serialising via Sexplib a data structure defined
recursively. Consider module M defined below; note how type foobar_t includes
a "with sexp" declaration, telling the Sexplib syntax extension to create
(de)serialisers automatically. However, type t cannot rely on that automatism,
because type declarations with the "as" operator are not fully supported.
Therefore, I need to create the (de)serialisers for this type manually.
module M:
sig
type 'a foobar_t =
[ `Foo of int
| `Bar of 'a list
] with sexp
type t = private [< 'a foobar_t ] as 'a
val foo: int -> t
val bar: t list -> t
end =
struct
type 'a foobar_t =
[ `Foo of int
| `Bar of 'a list
] with sexp
type t = 'a foobar_t as 'a
let foo x = `Foo x
let bar x = `Bar x
end
So basically the problem is creating the functions with the following signatures:
val sexp_of_t: t -> Sexplib.Sexp.t
val t_of_sexp: Sexplib.Sexp.t -> t
Using as base the automatically created functions whose signatures are as follows:
val sexp_of_foobar_t: ('a -> Sexplib.Sexp.t) -> 'a foobar_t -> Sexplib.Sexp.t
val foobar_t_of_sexp: (Sexplib.Sexp.t -> 'a) -> Sexplib.Sexp.t -> 'a foobar_t
But in practice, I'm having trouble seeing how these later functions can
be used. The problem lies in their recursive definition: how would I
break it? (And yes, I realise that the definition of type t is unusual,
but it's extremely convenient for avoiding a lot of explicit annotations
and coercions [1]).
Thanks for your help!
Best regards,
Dario Teixeira
[1] http://groups.google.com/group/fa.caml/browse_thread/thread/7552095ab859fb5f/9c4a6fd19812fbcc
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: [Caml-list] Unusual type declaration and Sexplib
2009-02-22 20:59 Unusual type declaration and Sexplib Dario Teixeira
@ 2009-02-23 10:27 ` Jacques Garrigue
2009-02-23 16:50 ` Dario Teixeira
0 siblings, 1 reply; 3+ messages in thread
From: Jacques Garrigue @ 2009-02-23 10:27 UTC (permalink / raw)
To: darioteixeira; +Cc: caml-list
From: Dario Teixeira <darioteixeira@yahoo.com>
> I'm having some trouble serialising via Sexplib a data structure defined
> recursively. Consider module M defined below; note how type foobar_t includes
> a "with sexp" declaration, telling the Sexplib syntax extension to create
> (de)serialisers automatically. However, type t cannot rely on that automatism,
> because type declarations with the "as" operator are not fully supported.
> Therefore, I need to create the (de)serialisers for this type manually.
You program below is exactly equivalent to the following, without as.
Or si your real code something different?
module M:
sig
type 'a foobar_t =
[ `Foo of int
| `Bar of 'a list ]
type t = private [< t foobar_t ]
val foo: int -> t
val bar: t list -> t
end =
struct
type 'a foobar_t =
[ `Foo of int
| `Bar of 'a list ]
type t = t foobar_t
let foo x = `Foo x
let bar x = `Bar x
end
Jacques Garrigue
> module M:
> sig
> type 'a foobar_t =
> [ `Foo of int
> | `Bar of 'a list
> ] with sexp
>
> type t = private [< 'a foobar_t ] as 'a
>
> val foo: int -> t
> val bar: t list -> t
> end =
> struct
> type 'a foobar_t =
> [ `Foo of int
> | `Bar of 'a list
> ] with sexp
>
> type t = 'a foobar_t as 'a
>
> let foo x = `Foo x
> let bar x = `Bar x
> end
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: [Caml-list] Unusual type declaration and Sexplib
2009-02-23 10:27 ` [Caml-list] " Jacques Garrigue
@ 2009-02-23 16:50 ` Dario Teixeira
0 siblings, 0 replies; 3+ messages in thread
From: Dario Teixeira @ 2009-02-23 16:50 UTC (permalink / raw)
To: Jacques Garrigue; +Cc: caml-list
Hi,
> You program below is exactly equivalent to the following,
> without as. Or is your real code something different?
You're right, the formulation without 'as' is simpler, and Sexplib handles
it just fine. The real code adds a phantom type variable to t, and the
advantage of using 'as' was making the phantomness obvious:
type +'a t = private [< 'b node_t ] as 'b
versus
type +'a t = private [< 'a t node_t ]
But in this case, 'as' does raise more trouble than it's worth...
Anyway, issue solved -- thanks!
Best regards,
Dario Teixeira
^ permalink raw reply [flat|nested] 3+ messages in thread
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