Yes. That is correct.

Amir

On Wed, Nov 5, 2014 at 1:56 PM, Roelof Wobben <r.wobben@home.nl> wrote:

Oke,

Now the line means that that I call the function length2 with the list and acc as 0 the first time.

Roelof

Amirhossein Vakili schreef op 5-11-2014 19:53:

Hi Roelof,

Your last line is not a correct term. "acc 0 list2 list" means that "acc" is a function, which has not been defined anywhere, and as a result, it is unbounded. The correct form is the following:

let length list =
           let rec length2 list2 acc =
           match list2 with
           | [] -> acc
           | x::xs -> length2 xs (acc + 1)
       in length2 list 0;;

Hope this helps,

Amir

On Wed, Nov 5, 2014 at 1:46 PM, Roelof Wobben <r.wobben@home.nl> wrote:

Hello,

I asked this question also on the beginners list but till now no respons.

I have this :

let length list =
    let rec length2 list2 acc =
        match list2 with
           | [] -> acc
           | x::xs -> length2 xs (acc + 1)
    in acc 0 list2 list ;;

But as soon as I copie it into the ocaml prompt I see a message that the acc in the part in acc 0 list2 list is unbound.

Roelof



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