[Caml-list] why is the variable here unbound.

[Caml-list] why is the variable here unbound.

[Roelof Wobben]

Hello,

I asked this question also on the beginners list but till now no respons.

I have this :

let length list =
     let rec length2 list2 acc =
         match list2 with
            | [] -> acc
            | x::xs -> length2 xs (acc + 1)
     in acc 0 list2 list ;;

But as soon as I copie it into the ocaml prompt I see a message that the 
acc in the part in acc 0 list2 list is unbound.

Roelof

Re: [Caml-list] why is the variable here unbound.

[Malcolm Matalka]

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I think you mean ... in length2 list []
Den 5 nov 2014 19:47 skrev "Roelof Wobben" <r.wobben@home.nl>:

> Hello,
>
> I asked this question also on the beginners list but till now no respons.
>
> I have this :
>
> let length list =
>     let rec length2 list2 acc =
>         match list2 with
>            | [] -> acc
>            | x::xs -> length2 xs (acc + 1)
>     in acc 0 list2 list ;;
>
> But as soon as I copie it into the ocaml prompt I see a message that the
> acc in the part in acc 0 list2 list is unbound.
>
> Roelof
>
>
>
> --
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>

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Re: [Caml-list] why is the variable here unbound.

[Roelof Wobben]

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