From: Philippe Wang <lists@philippewang.info>
To: Till Varoquaux <till.varoquaux@gmail.com>, ocaml ml <caml-list@inria.fr>
Subject: Re: [Caml-list] How do I get polymorphic partial application?
Date: Sat, 23 Jun 2007 23:41:00 +0200 [thread overview]
Message-ID: <467D936C.5020501@philippewang.info> (raw)
In-Reply-To: <9d3ec8300706231155p2429504ay6395ea0580756dc7@mail.gmail.com>
Till Varoquaux wrote:
> Humm... I have a small issue here: I need to get the result of the
> partial application of a polymorphic function. Since variable are
> generalized in Let it is generally advised to use eta expansions,
> (i.e transform to a total application).
> sometimes eta expansions just won't do the trick, consider:
>
> let cntTag start=
> let cnt=ref start in
> fun v -> ((incr cnt;!cnt),v)
>
> the partial application is not fully polymorphic
>
> let tag1 = cntTag 1
>
> has type
>
> val tag1 : '_a -> int * '_a = <fun>
>
> the eta expanded equivalent doesn't have the same semantic (it
> actually seems even less useful):
>
> let tag1 x= cntTag 1 x
>
> Is there an elegant solution to that problem?
> Cheers,
> Till
>
Hi,
I think you should not try to "hide" that ugly side effect...
If you do something like
let rec f a = incr x ; a
and x = ref 42
and start s = x := s ;;
then you don't need to ask yourself how to bypass the type checker...
Still, you can hide things in a module...
module X :
sig
val f : 'a -> int * 'a
val start : int -> unit
end = struct
let rec f a = incr x ; !x, a
and x = ref 42
and start s = x := s
end
(* include X *)
(only Obj.magic can do exactly what you're asking for -- except the
"elegant" part)
--
Philippe Wang
mail[at]philippewang.info
next prev parent reply other threads:[~2007-06-23 21:41 UTC|newest]
Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top
2007-06-23 18:55 Till Varoquaux
2007-06-23 21:41 ` Philippe Wang [this message]
2007-06-23 21:49 ` [Caml-list] " Lukasz Stafiniak
2007-06-23 22:09 ` Till Varoquaux
2007-06-23 22:25 ` Lukasz Stafiniak
2007-06-23 22:11 ` Philippe Wang
2007-06-23 22:28 ` Lukasz Stafiniak
2007-06-23 22:07 ` Zheng Li
2007-06-23 22:09 ` Zheng Li
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