From: Warren Harris <warren@kontiki.com>
To: caml-list@inria.fr
Subject: [Caml-list] module type constraints problem
Date: Wed, 28 May 2003 12:55:38 -0700 [thread overview]
Message-ID: <3ED5143A.4000706@kontiki.com> (raw)
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Hi. I'm wondering if someone on this mailing list can help me with a
module type problem. What I would like to achieve is an iteration
abstraction (module) that is parameterized by the node and element type
of the data to be iterated over. I want to implement this abstraction
for different data types including lists, and a language expression type.
In the list case, the element type is abstract ('a), and the node type
is 'a list.
In the expr case, the element type is expr (the exprs themselves, not
some sub-element of the exprs), and the node type is also expr.
Here's my module type:
module type Iter =
sig
type 'a t
val iter : ('a -> unit) -> 'a t -> unit
end
and here's the list implementation (works great):
module ListIter : Iter =
struct
type 'a t = 'a list
let iter f l = List.iter f l
end
Here's a simlified version of my expr type:
type expr =
Expr of int * expr * expr
| Int of int
| Unit
But this implementation of the Iter module won't type check:
module ExprIter : Iter =
struct
type 'a t = expr
let rec iter f e =
f e;
match e with
Expr(i, a, b) -> iter f a; iter f b
| e -> ()
end
Signature mismatch:
Modules do not match:
sig type 'a t = expr val iter : (expr -> 'a) -> expr -> unit end
is not included in
Iter
Values do not match:
val iter : (expr -> 'a) -> expr -> unit
is not included in
val iter : ('a -> unit) -> 'a t -> unit
Adding explicit constraints to the parameters of the iter function don't
help either:
module ExprIter : Iter =
struct
type 'a t = expr
let rec iter (f:'a -> unit) (e:'a t) =
f e;
match e with
Expr(i, a, b) -> iter f a; iter f b
| e -> ()
end
Signature mismatch:
Modules do not match:
sig type 'a t = expr val iter : (('a t as 'a) -> unit) -> 'a ->
unit end
is not included in
Iter
Values do not match:
val iter : (('a t as 'a) -> unit) -> 'a -> unit
is not included in
val iter : ('a -> unit) -> 'a t -> unit
Is there some additional way to constrain this problem such that the
type checker will accept it? If you look closely, 'a t = 'a = expr yet
the type checker is failing to deduce the equality of the two iter
function types.
Any help would be greatly appreciated,
Warren
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next reply other threads:[~2003-05-28 19:55 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-05-28 19:55 Warren Harris [this message]
2003-05-28 22:49 ` brogoff
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