* [Caml-list] ref
@ 2003-02-08 18:41 altavillasalvatore
2003-02-09 0:06 ` Alessandro Baretta
0 siblings, 1 reply; 3+ messages in thread
From: altavillasalvatore @ 2003-02-08 18:41 UTC (permalink / raw)
To: caml-list
Hi all,
my problem is this:
let r =
let a= ("b" , "c") in
let f = ref "" in
let g = ref "" in
f:= fst a;
g:= snd a;
!f,!g;;
val r : string * string = "b", "c"
I would want to call "a" one single time but....
let r =
let a= ("b" , "c") in
let f = ref "" in
let g = ref "" in
f,g := a;
!f, !g ;;
Characters 68-71:
This expression has type string ref * string ref but is here used with type
(string * string) ref
Regards.
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^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: [Caml-list] ref
2003-02-08 18:41 [Caml-list] ref altavillasalvatore
@ 2003-02-09 0:06 ` Alessandro Baretta
2003-02-09 0:17 ` William Lovas
0 siblings, 1 reply; 3+ messages in thread
From: Alessandro Baretta @ 2003-02-09 0:06 UTC (permalink / raw)
To: altavillasalvatore; +Cc: caml-list
altavillasalvatore@libero.it wrote:
> f,g := a;
> !f, !g ;;
You are asking too much of the assignment operator. You must
remember that Ocaml does not support operator overloading,
so you cannot define a
val (:=) : 'a ref -> 'a -> unit
and a
val (:=) : ('a * 'b) ref -> ('a * 'b) -> unit
This would require a form of "generic overloading" of (:=)
over all tuple types. This is really a little too much, I think.
BTW, are you sure you need references?
Alex
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^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: [Caml-list] ref
2003-02-09 0:06 ` Alessandro Baretta
@ 2003-02-09 0:17 ` William Lovas
0 siblings, 0 replies; 3+ messages in thread
From: William Lovas @ 2003-02-09 0:17 UTC (permalink / raw)
To: caml-list; +Cc: altavillasalvatore
On Sun, Feb 09, 2003 at 01:06:18AM +0100, Alessandro Baretta wrote:
>
>
> altavillasalvatore@libero.it wrote:
>
> >f,g := a;
> >!f, !g ;;
>
> You are asking too much of the assignment operator. You must
> remember that Ocaml does not support operator overloading,
> so you cannot define a
> val (:=) : 'a ref -> 'a -> unit
>
> and a
> val (:=) : ('a * 'b) ref -> ('a * 'b) -> unit
>
> This would require a form of "generic overloading" of (:=)
> over all tuple types. This is really a little too much, I think.
I think you mean for your second example to be:
val (:=) : ('a ref * 'b ref) -> ('a * 'b) -> unit
What you originally wrote,
val (:=) : ('a * 'b) ref -> ('a * 'b) -> unit ,
is just a more specific instance of
val (:=) : 'a ref -> 'a -> unit .
The original poster could accomplish his goal with something like:
let (a1,a2) = a in
f := a1;
g := a2;
!f, !g;;
but ...
> BTW, are you sure you need references?
... i agree that this is probably the right question to be asking :)
cheers,
William
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