From: Alessandro Baretta <alex@baretta.com>
To: climb <onlyclimb@163.com>
Cc: "caml-list@inria.fr" <caml-list@inria.fr>
Subject: [Caml-list] Re: how to start
Date: Thu, 17 Oct 2002 02:58:17 +0200 [thread overview]
Message-ID: <3DAE0B29.4090305@baretta.com> (raw)
In-Reply-To: <200210161407.g9GE7r505067@concorde.inria.fr>
climb wrote:
> Dear caml-list
>
> i am a new commer of Caml language.
Welcome on board!
> and start with online mannul
> i am confused at this sentence in Chapter 1
> # type idref={ mutable id : 'a. 'a -> 'a};;
> what does "." mean?
'a. 'a -> 'a
This is read as: "For every type 'a, a function from 'a to
'a". In this context 'a is a type variable. The type
variable preceding the "." are "universally quantified":
this is where the "For every type ..." comes into the game.
This basically states that the type of id is polymorphic: 'a
-> 'a is a type schema as opposed to a specific type. Many
different types fit this schema:
int -> int
string -> string
(int -> int) -> (int -> int), and so on.
The type schema 'a. 'a -> 'a is entirely equivalent to the
axiom schema of propositional calculus A => A: "If A then
A." A stands for *any* proposition, not for any one specific
proposition.
> why i can not write
> # type intidref= { mutable id : int. int->int};;
This does not make sense because "int" is a type value and
not a type variable.
Alex
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next prev parent reply other threads:[~2002-10-17 0:47 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2002-10-16 14:07 climb
2002-10-17 0:58 ` Alessandro Baretta [this message]
2002-10-17 17:00 climb
2002-10-18 7:28 ` [Caml-list] Re: how to start Florian Hars
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