Re: [Caml-list] converting a list to a Stream

[Sylvain Pogodalla <Sylvain.Pogodalla@xrce.xerox.com>]

Terrence Brannon wrote:
> 
> How does one convert a list to a stream?
> 
> # let c = [1; 2; 3 ];;
> val c : int list = [1; 2; 3]
> # Stream_of_list c;;
> Characters 0-16:
> Unbound constructor Stream_of_list
> # stream_of_list c;;
> Characters 0-14:
> Unbound value stream_of_list

To use a function defined for a module, you call it with the syntax :

Module.function arg

Here, you have :
# let l=[1; 2; 3 ];;
val l : int list = [1; 2; 3]
# Stream.of_list l;;
- : int Stream.t = <abstr>

Or, if you don't want to have to prefix the function with the module
name, you can open it :
# open Stream;;
# let l=[1; 2; 3 ];;
val l : int list = [1; 2; 3]
# of_list l;;

S.
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