From: oleg@pobox.com
To: Andrej.Bauer@andrej.com, jtbryant@valdosta.edu
Cc: caml-list@inria.fr
Subject: Amb
Date: Sat, 10 Feb 2007 03:15:56 -0800 (PST) [thread overview]
Message-ID: <20070210111556.3436EAB40@Adric.metnet.fnmoc.navy.mil> (raw)
Andrej Bauer wrote:
> let me point out that amb is supposed to work as an _angelic_
> nondeterministic choice operator. This means it must choose a value
> that, if at all possible, leads to successful completion of the
> computation.... The scheme implementation involves callcc magic.
> If anyone knows a reasonable implementation of amb, I'd be
> interested to know.
Here it is. Ocaml has something better than call/cc: delimited
continuations. So, amb is trivially implementable, in two lines of
code. We also need a `toplevel function', to tell us if the overall
computation succeeded. One may think of it as St.Peter at the
gate. For now, we take a computation that raises no exception as
successful. In general, even non-termination within a branch can be
dealt with intelligently (cf. `cooperative' threading which must yield
from time to time).
Regarding effects incurred while evaluating branches: one deal with
them as one deal with effects when implementing any transactional
mechanism: you prohibit them, you log the updates, you log the state
before the beginning so to undo, you use zipper for functional
`mutations' (which can be done with delimited continuations, too), you
operate in a sandbox, etc. The ZFS talk gives an example:
http://pobox.com/~oleg/ftp/Computation/Continuations.html#zipper-fs
Here are the tests. The second one requires a three-step clairvoyance:
let test1 () =
let v =
if (amb [(fun _ -> false); (fun _ -> true)]) then
7
else failwith "Sinner!"
in Printf.printf "got the result %d\n" v;;
let test1r = toplevel test1;;
(* got the result 7 *)
(* Test that invokes the Pythagorean spirit *)
let numbers = List.map (fun n -> (fun () -> n)) [1;2;3;4;5];;
let pyth () =
let (v1,v2,v3) =
let i = amb numbers in
let j = amb numbers in
let k = amb numbers in
if i*i + j*j = k*k then (i,j,k) else failwith "too bad"
in Printf.printf "got the result (%d,%d,%d)\n" v1 v2 v3;;
let pythr = toplevel pyth;;
(* got the result (3,4,5) *)
(* Open the DelimCC library
http://pobox.com/~oleg/ftp/Computation/Continuations.html#caml-shift
*)
open Delimcc;;
let shift p f = take_subcont p (fun sk () ->
push_prompt p (fun () -> (f (fun c ->
push_prompt p (fun () -> push_subcont sk c)))))
;;
(* How evaluation has finished *)
type res =
Done (* Finished with the result *)
| Exc of exn (* Got an exception -- no good *)
| Choices of (unit -> res) list (* Alternative universes *)
exception Amb (* Raise when all choices are bad *)
;;
let topprompt = new_prompt ();;
(* If it looks like an OS scheduler, it's because it is *)
let toplevel thunk =
let rec loop queue = function
| Done (* evaluation of a branch finished successfully *)
-> ()
| Exc _ -> try_another queue
| Choices more -> (* OK, add them to the end: breadth-first *)
try_another (queue @ more)
and try_another = function
| [] -> raise Amb (* No more choices *)
| h::t -> loop t (try h () with e -> Exc e)
in
loop [] (push_prompt topprompt
(fun () -> try let _ = thunk () in Done with e -> Exc e))
;;
(* Split the universe. Something like `fork (2)' *)
let amb choices = shift topprompt (fun sk ->
Choices (List.map (fun choice -> (fun () -> sk choice)) choices));;
next reply other threads:[~2007-02-10 11:17 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2007-02-10 11:15 oleg [this message]
-- strict thread matches above, loose matches on Subject: below --
2007-02-09 21:31 Amb Jonathan Bryant
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