From: Michel Mauny <Michel.Mauny@inria.fr>
To: "Beck01, Wolfgang" <BeckW@t-systems.com>
Cc: caml-list@inria.fr
Subject: Re: [Caml-list] camlp4o and lazy: pr_o: not impl: expr; tag = 19
Date: Tue, 3 Jan 2006 19:11:11 +0100 [thread overview]
Message-ID: <20060103181111.GA12190@quincy.inria.fr> (raw)
In-Reply-To: <97A461F3EE5284469E41ED3728202F41121F18@S4DE9JSAAMW.ost.t-com.de>
This is a bug, and I've fixed it in the CVS. Note that you have
the same (buggy) behavior with <:expr< assert e >>.
Both of them happen only when pretty-printing the result, as done by
"camlp4o ./g3.cmo pr_o.cmo". If you use "camlp4o ./g3.cmo" as a
preprocessor to ocamlçocamlopt (through the -pp option), then the
syntax tree produced by camlp4o is correct.
Thanks,
-- Michel
Beck01, Wolfgang wrote/écrivait (Tue, Jan 03, 2006 at 03:31:05PM +0100):
> During the holidays I tried to get finally a clue about camlp4.
>
> When I have a small grammar like this:
>
> open Pcaml
> EXTEND
> expr:
> [ [
> "bla" ->
> let fe = <:expr< tst() >>
> in
> let lzy = <;expr< lazy $fe$ >>
> in
> <:expr< do_something $lzy$ >>
> ] ]
> ;
> END
>
> and compile it to g3.cmo with
>
> ocamlc -pp "camlp4o pa_extend.cmo q_MLast.cmo" -I +camlp4 -c g3.ml
>
> and pass a file containing a bla through
>
> camlp4o ./g3.cmo pr_o.cmo bla.ml
>
> I get
> let _ = do_something<pr_o: not impl: expr; tag = 19>
>
> There seems to be an issue with <:expr< lazy ... When I replace
> 'lazy' with 'lazi' everything works as expected:
>
> let _ = do_someting (lazi (tst ()))
>
> Any idea what's wrong here?
>
>
> Wolfgang
> --
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prev parent reply other threads:[~2006-01-03 18:11 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2006-01-03 14:31 Beck01, Wolfgang
2006-01-03 18:11 ` Michel Mauny [this message]
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