* [Caml-list] ocamlyacc help
@ 2005-09-10 10:40 Jonathan Roewen
2005-09-10 14:14 ` Eric Cooper
0 siblings, 1 reply; 2+ messages in thread
From: Jonathan Roewen @ 2005-09-10 10:40 UTC (permalink / raw)
To: caml-list
Hi,
I'm trying to write a parser, but I've become very unstuck.
I want to parse a string of format:
(OP FLOAT*)* and generate a (char * float list) list.
The problem I have is I don't know how to generate further tuples.
Jonathan
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: [Caml-list] ocamlyacc help
2005-09-10 10:40 [Caml-list] ocamlyacc help Jonathan Roewen
@ 2005-09-10 14:14 ` Eric Cooper
0 siblings, 0 replies; 2+ messages in thread
From: Eric Cooper @ 2005-09-10 14:14 UTC (permalink / raw)
To: caml-list
On Sat, Sep 10, 2005 at 10:40:28PM +1200, Jonathan Roewen wrote:
> I want to parse a string of format:
>
> (OP FLOAT*)* and generate a (char * float list) list.
>
> The problem I have is I don't know how to generate further tuples.
(Re)read the Dragon book on LALR parsing!
%token <char> OP
%token <float> FLOAT
%start expr
%type <(char * float list) list> expr
%%
expr:
op_list { List.rev $1 }
;
op_list:
/* empty */ { [] }
| op_list OP float_list { ($2, List.rev $3) :: $1 }
;
float_list:
/* empty */ { [] }
| float_list FLOAT { $2 :: $1 }
;
Note that it's good practice to write rules for "lists of things" in a
left-recursive style, because that allows LALR parsers to handle
arbitrarily-long lists without stack overflow. In OCaml, where the
natural semantic action for a list is to build a list, you probably want
to build the list backwards (i.e. $2 :: $1 instead of $1 @ [$2]),
and then reverse it where it's used (if that's even necessary).
--
Eric Cooper e c c @ c m u . e d u
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