* [Caml-list] Indeterminate Initialization: Is it a Bug?
@ 2004-04-01 9:04 Richard Cole
2004-04-01 13:37 ` Xavier Leroy
0 siblings, 1 reply; 2+ messages in thread
From: Richard Cole @ 2004-04-01 9:04 UTC (permalink / raw)
To: caml-list
Hi,
There seems to be a difference in initialization behaviour using the
native compiler depending on whether a module contains non "external"
calls. Let me give an example:
#!/bin/bash
rm -f test_funky.ml funky.ml ml_funky.c *funky*.cm* *funky*.a *funky*.so
echo '
Printf.fprintf stderr "Test.Init\n"; flush stderr ;;
open Funky ;;
funky 4 ;;
' > test_funky.ml
echo '
#include <caml/mlvalues.h>
#include <caml/memory.h>
#include <stdio.h>
value ml_funky(value v)
{
CAMLparam1(v);
int i = Int_val(v) + 1;
fprintf(stderr, "ML_FUNKY!\n"); fflush(stderr);
CAMLreturn(Val_int(i));
};
' > ml_funky.c
echo '
external funky : int -> int = "ml_funky" ;;
Printf.fprintf stderr "Funky.Init.\n"; flush stderr ;;
' > funky.ml
gcc -Wall -c ml_funky.c -I/usr/local/godi/lib/ocaml/std-lib/
ocamlopt -c funky.ml
ocamlopt -c test_funky.ml
ocamlmklib -o funky ml_funky.o funky.cmx
ocamlopt -o test_funky.exe funky.cmxa test_funky.cmx -I .
./test_funky.exe
The output doesn't contain "Funky.Init". The problem is that the
initialization code in the funky module didn't get called. If I wrap the
functions as in:
#!/bin/bash
echo '
external ml_funky: int -> int = "ml_funky" ;;
let funky x = ml_funky x ;;
Printf.fprintf stderr "Init.\n"; flush stderr ;;
' > funky.ml
ocamlopt -c funky.ml
ocamlmklib -o funky ml_funky.o funky.cmx
ocamlopt -o test_funky.exe funky.cmxa test_funky.ml -I .
./test_funky.exe
Then the initialization code, namely the printf statement in flunky.ml
is called.
So I have the following question: Is there some way to guarrentee that
modules are initialized exactly once? Does the development team see the
current situation, whereby intialization depends on wheher there is a
non external method in the module that is called, as a problem? Can it
be fixed?
I should mention that I'm using Godi with godi-ocaml version 3.07pl2 and
fairly vanilla Redhat 9. Is this problem replicatable on other platforms?
Why do I want to have intialization code always called in my modules.
Mostly because I want the following initialization code to work without
having to add a layer of indirection to my wrapper modules.
exception NotFound ;;
let _ = Callback.register "Funky.NotFound" NotFound ;;
best regards,
Richard.
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^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: [Caml-list] Indeterminate Initialization: Is it a Bug?
2004-04-01 9:04 [Caml-list] Indeterminate Initialization: Is it a Bug? Richard Cole
@ 2004-04-01 13:37 ` Xavier Leroy
0 siblings, 0 replies; 2+ messages in thread
From: Xavier Leroy @ 2004-04-01 13:37 UTC (permalink / raw)
To: Richard Cole; +Cc: caml-list
> There seems to be a difference in initialization behaviour using the
> native compiler depending on whether a module contains non "external"
> calls. [...]
> The output doesn't contain "Funky.Init". The problem is that the
> initialization code in the funky module didn't get called. If I wrap the
> functions as in:
>
> #!/bin/bash
> echo '
> external ml_funky: int -> int = "ml_funky" ;;
> let funky x = ml_funky x ;;
> Printf.fprintf stderr "Init.\n"; flush stderr ;;
> ' > funky.ml
A simpler solution is to define "funky" as an external in the .ml file
but declare it as a regular value in the .mli file:
.ml: external funky: int -> int = "ml_funky"
.mli: val funky: int -> int
> So I have the following question: Is there some way to guarrentee that
> modules are initialized exactly once? Does the development team see the
> current situation, whereby intialization depends on wheher there is a
> non external method in the module that is called, as a problem? Can it
> be fixed?
The behavior you observe is a consequence of the link-time elimination
of unreferenced .cma or .cmxa members. An "external" declaration in a
module interface is like a type declaration: using it elsewhere
doesn't create a reference to the implementation of the defining module.
You can turn off this link-time elimination using the -linkall flag,
either at library creation time (ocamlmklib), or at link-time (ocamlopt).
Then, all modules will be initialized exactly once and in the order
given, like you expect.
- Xavier Leroy
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