* [Caml-list] Recursive types and functors. @ 2003-03-26 6:28 David Brown 2003-03-26 8:25 ` Jean-Christophe Filliatre 0 siblings, 1 reply; 5+ messages in thread From: David Brown @ 2003-03-26 6:28 UTC (permalink / raw) To: Caml List I have a recursive type where I'd like one of the constructors of the type to contain a set of the type (or something like set). However, I can't figure out how to represent this. For example: type foo = | Integer of int | String of string | Set of FooSet module FooSet = Set.Make (struct type t = foo let compare = compare end) but this obviously doesn't work. I suspect putting type foo in a functor can somehow make it work, but I haven't quite figure out how to do it. Thanks, Dave Brown ------------------- To unsubscribe, mail caml-list-request@inria.fr Archives: http://caml.inria.fr Bug reports: http://caml.inria.fr/bin/caml-bugs FAQ: http://caml.inria.fr/FAQ/ Beginner's list: http://groups.yahoo.com/group/ocaml_beginners ^ permalink raw reply [flat|nested] 5+ messages in thread
* Re: [Caml-list] Recursive types and functors. 2003-03-26 6:28 [Caml-list] Recursive types and functors David Brown @ 2003-03-26 8:25 ` Jean-Christophe Filliatre 2003-03-26 8:57 ` David Brown 2003-03-26 9:13 ` Claude Marche 0 siblings, 2 replies; 5+ messages in thread From: Jean-Christophe Filliatre @ 2003-03-26 8:25 UTC (permalink / raw) To: David Brown; +Cc: Caml List [-- Attachment #1: message body and .signature --] [-- Type: text/plain, Size: 3096 bytes --] David Brown writes: > I have a recursive type where I'd like one of the constructors of the > type to contain a set of the type (or something like set). However, I > can't figure out how to represent this. > > For example: > > type foo = > | Integer of int > | String of string > | Set of FooSet > > module FooSet = Set.Make (struct type t = foo let compare = compare end) > > but this obviously doesn't work. I'm pretty sure this has already been discussed on this list, but I couldn't find the related thread in the archives... A (too) naive solution could be to make a polymorphic instance of the Set module (either by adding an argument 'a everywhere in signatures OrderedType and S, or by copying the functor body and replacing Ord.compare by compare); then you have polymorphic sets, say 'a Set.t, balanced using compare, and you can define type foo = Integer of int | ... | Set of foo Set.t Unfortunately this doesn't work because sets themselves shouldn't be compared with compare, but with Set.compare (see set.mli). And then you point out the main difficulty: comparing values in type foo requires to be able to compare sets of foo, and comparing sets requires to *implement* sets and thus to compare values in foo. Fortunately, there is another solution (though a bit more complex). First we define a more generic type 'a foo where 'a will be substituted later by sets of foo: type 'a foo = Integer of int | ... | Set of 'a Then we implement a variant of module Set which implements sets given the following signature: module type OrderedType = sig type 'a t val compare: ('a -> 'a -> int) -> 'a t -> 'a t -> int end that is where elements are in the polymorphic type 'a t and where the comparison function depends on a comparison function for arguments in 'a (which will represent the sets, in fine). The functor implements a type t for sets using balanced trees, as usual, and defines the type of elements elt to be t Ord.t: module Make(Ord: OrderedType) = struct type elt = t Ord.t and t = Empty | Node of t * elt * t * int Right after, it implements comparison over elements and sets in a mutually recursive way: let rec compare_elt x y = Ord.compare compare x y and compare = ... (usual comparison of sets, using compare_elt) The remaining of the functor is exactly the same as for Set, with compare_elt used instead of Ord.compare. I attach the implementation of this module. There is (at least) another solution: to use a set implementation where comparison does not require a comparison of elements. This is possible if, for instance, you are performing hash-consing on type foo (which result in tagging foo values with integers, then used in the comparison). This solution is used in Claude Marché's regexp library (http://www.lri.fr/~marche/regexp/) and uses a hash-consing technique available here: http://www.lri.fr/~filliatr/software.en.html Hope this helps, -- Jean-Christophe Filliâtre (http://www.lri.fr/~filliatr) [-- Attachment #2: mset.mli --] [-- Type: application/octet-stream, Size: 5082 bytes --] (***********************************************************************) (* *) (* Objective Caml *) (* *) (* Xavier Leroy, projet Cristal, INRIA Rocquencourt *) (* *) (* Copyright 1996 Institut National de Recherche en Informatique et *) (* en Automatique. All rights reserved. This file is distributed *) (* under the terms of the GNU Library General Public License. *) (* *) (***********************************************************************) (* $Id: pset.mli,v 1.2 2002/02/22 15:54:43 filliatr Exp $ *) (* Module [Mset]: variant of module [Set] to build a type and sets of elements in this type in a mutually recursive way. *) module type OrderedType = sig type 'a t val compare: ('a -> 'a -> int) -> 'a t -> 'a t -> int end (* The input signature of the functor [Mset.Make]. ['a t] is the type of the set elements where ['a] will be substituted by the type for sets of such elements. [compare] is a total ordering function over the set elements, given a total ordering function over sets. *) module Make(Ord: OrderedType): (* Functor building an implementation of the set structure *) sig type t (* The type of sets. *) type elt = t Ord.t (* The type of the set elements. *) val empty: t (* The empty set. *) val is_empty: t -> bool (* Test whether a set is empty or not. *) val mem: elt -> t -> bool (* [mem x s] tests whether [x] belongs to the set [s]. *) val add: elt -> t -> t (* [add x s] returns a set containing all elements of [s], plus [x]. If [x] was already in [s], [s] is returned unchanged. *) val singleton: elt -> t (* [singleton x] returns the one-element set containing only [x]. *) val remove: elt -> t -> t (* [remove x s] returns a set containing all elements of [s], except [x]. If [x] was not in [s], [s] is returned unchanged. *) val union: t -> t -> t val inter: t -> t -> t val diff: t -> t -> t (* Union, intersection and set difference. *) val compare_elt: elt -> elt -> int (* Total ordering between elements. *) val compare: t -> t -> int (* Total ordering between sets. Can be used as the ordering function for doing sets of sets. *) val equal: t -> t -> bool (* [equal s1 s2] tests whether the sets [s1] and [s2] are equal, that is, contain equal elements. *) val subset: t -> t -> bool (* [subset s1 s2] tests whether the set [s1] is a subset of the set [s2]. *) val iter: (elt -> unit) -> t -> unit (* [iter f s] applies [f] in turn to all elements of [s]. The order in which the elements of [s] are presented to [f] is unspecified. *) val fold: (elt -> 'b -> 'b) -> t -> 'b -> 'b (* [fold f s a] computes [(f xN ... (f x2 (f x1 a))...)], where [x1 ... xN] are the elements of [s]. The order in which elements of [s] are presented to [f] is unspecified. *) val for_all: (elt -> bool) -> t -> bool (* [for_all p s] checks if all elements of the set satisfy the predicate [p]. *) val exists: (elt -> bool) -> t -> bool (* [exists p s] checks if at least one element of the set satisfies the predicate [p]. *) val filter: (elt -> bool) -> t -> t (* [filter p s] returns the set of all elements in [s] that satisfy predicate [p]. *) val partition: (elt -> bool) -> t -> t * t (* [partition p s] returns a pair of sets [(s1, s2)], where [s1] is the set of all the elements of [s] that satisfy the predicate [p], and [s2] is the set of all the elements of [s] that do not satisfy [p]. *) val cardinal: t -> int (* Return the number of elements of a set. *) val elements: t -> elt list (* Return the list of all elements of the given set. The returned list is sorted in increasing order with respect to the ordering [Ord.compare], where [Ord] is the argument given to [Set.Make]. *) val min_elt: t -> elt (* Return the smallest element of the given set (with respect to the [Ord.compare] ordering), or raise [Not_found] if the set is empty. *) val max_elt: t -> elt (* Same as [min_elt], but returns the largest element of the given set. *) val choose: t -> elt (* Return one element of the given set, or raise [Not_found] if the set is empty. Which element is chosen is unspecified, but equal elements will be chosen for equal sets. *) end [-- Attachment #3: mset.ml --] [-- Type: application/octet-stream, Size: 9891 bytes --] (***********************************************************************) (* *) (* Objective Caml *) (* *) (* Xavier Leroy, projet Cristal, INRIA Rocquencourt *) (* *) (* Copyright 1996 Institut National de Recherche en Informatique et *) (* en Automatique. All rights reserved. This file is distributed *) (* under the terms of the GNU Library General Public License. *) (* *) (***********************************************************************) (* $Id: pset.ml,v 1.1 2000/07/07 16:13:17 filliatr Exp $ *) (* Sets over ordered types *) module type OrderedType = sig type 'a t val compare: ('a -> 'a -> int) -> 'a t -> 'a t -> int end module type S = sig type elt type t val empty: t val is_empty: t -> bool val mem: elt -> t -> bool val add: elt -> t -> t val singleton: elt -> t val remove: elt -> t -> t val union: t -> t -> t val inter: t -> t -> t val diff: t -> t -> t val compare_elt : elt -> elt -> int val compare: t -> t -> int val equal: t -> t -> bool val subset: t -> t -> bool val iter: (elt -> unit) -> t -> unit val fold: (elt -> 'b -> 'b) -> t -> 'b -> 'b val for_all: (elt -> bool) -> t -> bool val exists: (elt -> bool) -> t -> bool val filter: (elt -> bool) -> t -> t val partition: (elt -> bool) -> t -> t * t val cardinal: t -> int val elements: t -> elt list val min_elt: t -> elt val max_elt: t -> elt val choose: t -> elt end module Make(Ord: OrderedType) = struct type elt = t Ord.t and t = Empty | Node of t * elt * t * int let rec compare_elt x y = Ord.compare compare x y and compare_aux l1 l2 = match (l1, l2) with ([], []) -> 0 | ([], _) -> -1 | (_, []) -> 1 | (Empty :: t1, Empty :: t2) -> compare_aux t1 t2 | (Node(Empty, v1, r1, _) :: t1, Node(Empty, v2, r2, _) :: t2) -> let c = compare_elt v1 v2 in if c <> 0 then c else compare_aux (r1::t1) (r2::t2) | (Node(l1, v1, r1, _) :: t1, t2) -> compare_aux (l1 :: Node(Empty, v1, r1, 0) :: t1) t2 | (t1, Node(l2, v2, r2, _) :: t2) -> compare_aux t1 (l2 :: Node(Empty, v2, r2, 0) :: t2) and compare s1 s2 = compare_aux [s1] [s2] (* Sets are represented by balanced binary trees (the heights of the children differ by at most 2 *) let height = function Empty -> 0 | Node(_, _, _, h) -> h (* Creates a new node with left son l, value x and right son r. l and r must be balanced and | height l - height r | <= 2. Inline expansion of height for better speed. *) let create l x r = let hl = match l with Empty -> 0 | Node(_,_,_,h) -> h in let hr = match r with Empty -> 0 | Node(_,_,_,h) -> h in Node(l, x, r, (if hl >= hr then hl + 1 else hr + 1)) (* Same as create, but performs one step of rebalancing if necessary. Assumes l and r balanced. Inline expansion of create for better speed in the most frequent case where no rebalancing is required. *) let bal l x r = let hl = match l with Empty -> 0 | Node(_,_,_,h) -> h in let hr = match r with Empty -> 0 | Node(_,_,_,h) -> h in if hl > hr + 2 then begin match l with Empty -> invalid_arg "Set.bal" | Node(ll, lv, lr, _) -> if height ll >= height lr then create ll lv (create lr x r) else begin match lr with Empty -> invalid_arg "Set.bal" | Node(lrl, lrv, lrr, _)-> create (create ll lv lrl) lrv (create lrr x r) end end else if hr > hl + 2 then begin match r with Empty -> invalid_arg "Set.bal" | Node(rl, rv, rr, _) -> if height rr >= height rl then create (create l x rl) rv rr else begin match rl with Empty -> invalid_arg "Set.bal" | Node(rll, rlv, rlr, _) -> create (create l x rll) rlv (create rlr rv rr) end end else Node(l, x, r, (if hl >= hr then hl + 1 else hr + 1)) (* Same as bal, but repeat rebalancing until the final result is balanced. *) let rec join l x r = match bal l x r with Empty -> invalid_arg "Set.join" | Node(l', x', r', _) as t' -> let d = height l' - height r' in if d < -2 or d > 2 then join l' x' r' else t' (* Merge two trees l and r into one. All elements of l must precede the elements of r. Assumes | height l - height r | <= 2. *) let rec merge t1 t2 = match (t1, t2) with (Empty, t) -> t | (t, Empty) -> t | (Node(l1, v1, r1, h1), Node(l2, v2, r2, h2)) -> bal l1 v1 (bal (merge r1 l2) v2 r2) (* Same as merge, but does not assume anything about l and r. *) let rec concat t1 t2 = match (t1, t2) with (Empty, t) -> t | (t, Empty) -> t | (Node(l1, v1, r1, h1), Node(l2, v2, r2, h2)) -> join l1 v1 (join (concat r1 l2) v2 r2) (* Splitting *) let rec split x = function Empty -> (Empty, None, Empty) | Node(l, v, r, _) -> let c = compare_elt x v in if c = 0 then (l, Some v, r) else if c < 0 then let (ll, vl, rl) = split x l in (ll, vl, join rl v r) else let (lr, vr, rr) = split x r in (join l v lr, vr, rr) (* Implementation of the set operations *) let empty = Empty let is_empty = function Empty -> true | _ -> false let rec mem x = function Empty -> false | Node(l, v, r, _) -> let c = compare_elt x v in c = 0 || mem x (if c < 0 then l else r) let rec add x = function Empty -> Node(Empty, x, Empty, 1) | Node(l, v, r, _) as t -> let c = compare_elt x v in if c = 0 then t else if c < 0 then bal (add x l) v r else bal l v (add x r) let singleton x = Node(Empty, x, Empty, 1) let rec remove x = function Empty -> Empty | Node(l, v, r, _) -> let c = compare_elt x v in if c = 0 then merge l r else if c < 0 then bal (remove x l) v r else bal l v (remove x r) let rec union s1 s2 = match (s1, s2) with (Empty, t2) -> t2 | (t1, Empty) -> t1 | (Node(l1, v1, r1, h1), Node(l2, v2, r2, h2)) -> if h1 >= h2 then if h2 = 1 then add v2 s1 else begin let (l2, _, r2) = split v1 s2 in join (union l1 l2) v1 (union r1 r2) end else if h1 = 1 then add v1 s2 else begin let (l1, _, r1) = split v2 s1 in join (union l1 l2) v2 (union r1 r2) end let rec inter s1 s2 = match (s1, s2) with (Empty, t2) -> Empty | (t1, Empty) -> Empty | (Node(l1, v1, r1, _), t2) -> match split v1 t2 with (l2, None, r2) -> concat (inter l1 l2) (inter r1 r2) | (l2, Some _, r2) -> join (inter l1 l2) v1 (inter r1 r2) let rec diff s1 s2 = match (s1, s2) with (Empty, t2) -> Empty | (t1, Empty) -> t1 | (Node(l1, v1, r1, _), t2) -> match split v1 t2 with (l2, None, r2) -> join (diff l1 l2) v1 (diff r1 r2) | (l2, Some _, r2) -> concat (diff l1 l2) (diff r1 r2) let equal s1 s2 = compare s1 s2 = 0 let rec subset s1 s2 = match (s1, s2) with Empty, _ -> true | _, Empty -> false | Node (l1, v1, r1, _), (Node (l2, v2, r2, _) as t2) -> let c = compare_elt v1 v2 in if c = 0 then subset l1 l2 && subset r1 r2 else if c < 0 then subset (Node (l1, v1, Empty, 0)) l2 && subset r1 t2 else subset (Node (Empty, v1, r1, 0)) r2 && subset l1 t2 let rec iter f = function Empty -> () | Node(l, v, r, _) -> iter f l; f v; iter f r let rec fold f s accu = match s with Empty -> accu | Node(l, v, r, _) -> fold f l (f v (fold f r accu)) let rec for_all p = function Empty -> true | Node(l, v, r, _) -> p v && for_all p l && for_all p r let rec exists p = function Empty -> false | Node(l, v, r, _) -> p v || exists p l || exists p r let filter p s = let rec filt accu = function | Empty -> accu | Node(l, v, r, _) -> filt (filt (if p v then add v accu else accu) l) r in filt Empty s let partition p s = let rec part (t, f as accu) = function | Empty -> accu | Node(l, v, r, _) -> part (part (if p v then (add v t, f) else (t, add v f)) l) r in part (Empty, Empty) s let rec cardinal = function Empty -> 0 | Node(l, v, r, _) -> cardinal l + 1 + cardinal r let rec elements_aux accu = function Empty -> accu | Node(l, v, r, _) -> elements_aux (v :: elements_aux accu r) l let elements s = elements_aux [] s let rec min_elt = function Empty -> raise Not_found | Node(Empty, v, r, _) -> v | Node(l, v, r, _) -> min_elt l let rec max_elt = function Empty -> raise Not_found | Node(l, v, Empty, _) -> v | Node(l, v, r, _) -> max_elt r let choose = min_elt end ^ permalink raw reply [flat|nested] 5+ messages in thread
* Re: [Caml-list] Recursive types and functors. 2003-03-26 8:25 ` Jean-Christophe Filliatre @ 2003-03-26 8:57 ` David Brown 2003-03-26 15:59 ` brogoff 2003-03-26 9:13 ` Claude Marche 1 sibling, 1 reply; 5+ messages in thread From: David Brown @ 2003-03-26 8:57 UTC (permalink / raw) To: Caml List On Wed, Mar 26, 2003 at 09:25:13AM +0100, Jean-Christophe Filliatre wrote: > A (too) naive solution could be to make a polymorphic instance of the > Set module (either by adding an argument 'a everywhere in signatures > OrderedType and S, or by copying the functor body and replacing > Ord.compare by compare); then you have polymorphic sets, say 'a Set.t, > balanced using compare, and you can define Actually, my real case doesn't use sets, but a dynamic array implementation I made myself. I originally needed a functor because I needed an empty value to fill in past the used elements of the real array. What I ended up doing was filling in those elements with 'Obj.magic 0'. I don't really like walking outside of the type system, but since I never return them, I don't think it will be a problem. I still may try to figure out how to do it with the multiple functor approach, just so to learn how to do it. Thanks, Dave ------------------- To unsubscribe, mail caml-list-request@inria.fr Archives: http://caml.inria.fr Bug reports: http://caml.inria.fr/bin/caml-bugs FAQ: http://caml.inria.fr/FAQ/ Beginner's list: http://groups.yahoo.com/group/ocaml_beginners ^ permalink raw reply [flat|nested] 5+ messages in thread
* Re: [Caml-list] Recursive types and functors. 2003-03-26 8:57 ` David Brown @ 2003-03-26 15:59 ` brogoff 0 siblings, 0 replies; 5+ messages in thread From: brogoff @ 2003-03-26 15:59 UTC (permalink / raw) To: David Brown; +Cc: Caml List Hi Dave, There is no good solution for the problem (on the Subject: line that is) in the language. This is on my "most annoying flaws of OCaml" list. It's been dicussed several times on this list, and I think if you look on comp.lang.ml you'll see a recent thread there too. One solution you can use is the parametrization trick, that is, using an extra type variable to untie the recursive knot. You can do this with sets in OCaml by writing a polymorphic set functor, as others have explained. I don't know how you'd do something similar in SML, which doesn't have a polymorphic compare. This really needs a solution sooner rather than later. It makes me wonder what the point of functors is, since they're obviously not for abstract data type libraries. OK, I'm just kidding, but it is a nasty problem. -- Brian On Wed, 26 Mar 2003, David Brown wrote: > On Wed, Mar 26, 2003 at 09:25:13AM +0100, Jean-Christophe Filliatre wrote: > > > A (too) naive solution could be to make a polymorphic instance of the > > Set module (either by adding an argument 'a everywhere in signatures > > OrderedType and S, or by copying the functor body and replacing > > Ord.compare by compare); then you have polymorphic sets, say 'a Set.t, > > balanced using compare, and you can define > > Actually, my real case doesn't use sets, but a dynamic array > implementation I made myself. I originally needed a functor because I > needed an empty value to fill in past the used elements of the real > array. > > What I ended up doing was filling in those elements with 'Obj.magic 0'. > I don't really like walking outside of the type system, but since I > never return them, I don't think it will be a problem. > > I still may try to figure out how to do it with the multiple functor > approach, just so to learn how to do it. > > Thanks, > Dave > > ------------------- > To unsubscribe, mail caml-list-request@inria.fr Archives: http://caml.inria.fr > Bug reports: http://caml.inria.fr/bin/caml-bugs FAQ: http://caml.inria.fr/FAQ/ > Beginner's list: http://groups.yahoo.com/group/ocaml_beginners > ------------------- To unsubscribe, mail caml-list-request@inria.fr Archives: http://caml.inria.fr Bug reports: http://caml.inria.fr/bin/caml-bugs FAQ: http://caml.inria.fr/FAQ/ Beginner's list: http://groups.yahoo.com/group/ocaml_beginners ^ permalink raw reply [flat|nested] 5+ messages in thread
* Re: [Caml-list] Recursive types and functors. 2003-03-26 8:25 ` Jean-Christophe Filliatre 2003-03-26 8:57 ` David Brown @ 2003-03-26 9:13 ` Claude Marche 1 sibling, 0 replies; 5+ messages in thread From: Claude Marche @ 2003-03-26 9:13 UTC (permalink / raw) To: Jean-Christophe Filliatre; +Cc: David Brown, Caml List [-- Attachment #1: message body and .signature --] [-- Type: text/plain, Size: 1847 bytes --] >>>>> "JCF" == Jean-Christophe Filliatre <Jean-Christophe.Filliatre@lri.fr> writes: JCF> David Brown writes: >> I have a recursive type where I'd like one of the constructors of the >> type to contain a set of the type (or something like set). However, I >> can't figure out how to represent this. >> >> For example: >> >> type foo = >> | Integer of int >> | String of string >> | Set of FooSet >> >> module FooSet = Set.Make (struct type t = foo let compare = compare end) >> >> but this obviously doesn't work. JCF> There is (at least) another solution: to use a set implementation JCF> where comparison does not require a comparison of elements. This is JCF> possible if, for instance, you are performing hash-consing on type foo JCF> (which result in tagging foo values with integers, then used in the JCF> comparison). This solution is used in Claude Marché's regexp library JCF> (http://www.lri.fr/~marche/regexp/) and uses a hash-consing technique JCF> available here: http://www.lri.fr/~filliatr/software.en.html Please find below a solution to your problem using this last solution. In fact this is independant of hash-consing, only tagging values with unique integers is important. hash-consing can be added if wanted. I hope my files are self-explanatory, but otherwise please ask me if you need help. The module Inttagset is a variant of patricia trees borrowed from JCF. The module Foo is what you are looking for, and test.ml is a example of use. JCF> Hope this helps, Me too ! -- | Claude Marché | mailto:Claude.Marche@lri.fr | | LRI - Bât. 490 | http://www.lri.fr/~marche/ | | Université de Paris-Sud | phoneto: +33 1 69 15 64 85 | | F-91405 ORSAY Cedex | faxto: +33 1 69 15 65 86 | [-- Attachment #2: inttagset.mli --] [-- Type: application/octet-stream, Size: 2047 bytes --] (* * Ptset: Sets of integers implemented as Patricia trees. * Copyright (C) 2000 Jean-Christophe FILLIATRE * * This software is free software; you can redistribute it and/or * modify it under the terms of the GNU Library General Public * License version 2, as published by the Free Software Foundation. * * This software is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. * * See the GNU Library General Public License version 2 for more details * (enclosed in the file LGPL). *) (*i $Id: inttagset.mli,v 1.1 2003/03/07 14:04:01 marche Exp $ i*) (*s Sets of integers implemented as Patricia trees. The following signature is exactly [Set.S with type elt = int], with the same specifications. This is a purely functional data-structure. The performances are always better than the standard library's module [Set], except for linear insertion (building a set by insertion of consecutive integers). *) type 'a t val empty : 'a t val is_empty : 'a t -> bool val mem : int -> 'a t -> bool val add : int -> 'a -> 'a t -> 'a t val singleton : int -> 'a -> 'a t val remove : int -> 'a t -> 'a t val union : 'a t -> 'a t -> 'a t val subset : 'a t -> 'a t -> bool val inter : 'a t -> 'a t -> 'a t val diff : 'a t -> 'a t -> 'a t val equal : 'a t -> 'a t -> bool val compare : 'a t -> 'a t -> int val elements : 'a t -> 'a list val choose : 'a t -> 'a val cardinal : 'a t -> int val iter : ('a -> unit) -> 'a t -> unit val fold : ('a -> 'b -> 'b) -> 'a t -> 'b -> 'b val for_all : ('a -> bool) -> 'a t -> bool val exists : ('a -> bool) -> 'a t -> bool val filter : ('a -> bool) -> 'a t -> 'a t val partition : ('a -> bool) -> 'a t -> 'a t * 'a t (*s Additional functions not appearing in the signature [Set.S] from ocaml standard library. *) (* [intersect u v] determines if sets [u] and [v] have a non-empty intersection. *) val intersect : 'a t -> 'a t -> bool [-- Attachment #3: inttagset.ml --] [-- Type: application/octet-stream, Size: 10945 bytes --] (* * Ptset: Sets of integers implemented as Patricia trees. * Copyright (C) 2000 Jean-Christophe FILLIATRE * * This software is free software; you can redistribute it and/or * modify it under the terms of the GNU Library General Public * License version 2, as published by the Free Software Foundation. * * This software is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. * * See the GNU Library General Public License version 2 for more details * (enclosed in the file LGPL). *) (*i $Id: inttagset.ml,v 1.1 2003/03/07 14:04:01 marche Exp $ i*) (*s Sets of integers implemented as Patricia trees, following Chris Okasaki and Andrew Gill's paper {\em Fast Mergeable Integer Maps} ({\tt\small http://www.cs.columbia.edu/\~{}cdo/papers.html\#ml98maps}). Patricia trees provide faster operations than standard library's module [Set], and especially very fast [union], [subset], [inter] and [diff] operations. *) (*s The idea behind Patricia trees is to build a {\em trie} on the binary digits of the elements, and to compact the representation by branching only one the relevant bits (i.e. the ones for which there is at least on element in each subtree). We implement here {\em little-endian} Patricia trees: bits are processed from least-significant to most-significant. The trie is implemented by the following type [t]. [Empty] stands for the empty trie, and [Leaf k] for the singleton [k]. (Note that [k] is the actual element.) [Branch (m,p,l,r)] represents a branching, where [p] is the prefix (from the root of the trie) and [m] is the branching bit (a power of 2). [l] and [r] contain the subsets for which the branching bit is respectively 0 and 1. Invariant: the trees [l] and [r] are not empty. *) type 'a t = | Empty | Leaf of int * 'a | Branch of int * int * 'a t * 'a t (*s Example: the representation of the set $\{1,4,5\}$ is $$\mathtt{Branch~(0,~1,~Leaf~4,~Branch~(1,~4,~Leaf~1,~Leaf~5))}$$ The first branching bit is the bit 0 (and the corresponding prefix is [0b0], not of use here), with $\{4\}$ on the left and $\{1,5\}$ on the right. Then the right subtree branches on bit 2 (and so has a branching value of $2^2 = 4$), with prefix [0b01 = 1]. *) (*s Empty set and singletons. *) let empty = Empty let is_empty = function Empty -> true | _ -> false let singleton k e = Leaf(k,e) (*s Testing the occurrence of a value is similar to the search in a binary search tree, where the branching bit is used to select the appropriate subtree. *) let zero_bit k m = (k land m) == 0 let rec mem k = function | Empty -> false | Leaf(j,_) -> k == j | Branch (_, m, l, r) -> mem k (if zero_bit k m then l else r) (*s The following operation [join] will be used in both insertion and union. Given two non-empty trees [t0] and [t1] with longest common prefixes [p0] and [p1] respectively, which are supposed to disagree, it creates the union of [t0] and [t1]. For this, it computes the first bit [m] where [p0] and [p1] disagree and create a branching node on that bit. Depending on the value of that bit in [p0], [t0] will be the left subtree and [t1] the right one, or the converse. Computing the first branching bit of [p0] and [p1] uses a nice property of twos-complement representation of integers. *) let lowest_bit x = x land (-x) let branching_bit p0 p1 = lowest_bit (p0 lxor p1) let mask p m = p land (m-1) let join (p0,t0,p1,t1) = let m = branching_bit p0 p1 in if zero_bit p0 m then Branch (mask p0 m, m, t0, t1) else Branch (mask p0 m, m, t1, t0) (*s Then the insertion of value [k] in set [t] is easily implemented using [join]. Insertion in a singleton is just the identity or a call to [join], depending on the value of [k]. When inserting in a branching tree, we first check if the value to insert [k] matches the prefix [p]: if not, [join] will take care of creating the above branching; if so, we just insert [k] in the appropriate subtree, depending of the branching bit. *) let match_prefix k p m = (mask k m) == p let rec ins e k = function | Empty -> Leaf (k,e) | Leaf(j,_) as t -> if j == k then t else join (k, Leaf (k,e), j, t) | Branch (p,m,t0,t1) as t -> if match_prefix k p m then if zero_bit k m then Branch (p, m, ins e k t0, t1) else Branch (p, m, t0, ins e k t1) else join (k, Leaf (k,e), p, t) let add k e t = ins e k t (*s The code to remove an element is basically similar to the code of insertion. But since we have to maintain the invariant that both subtrees of a [Branch] node are non-empty, we use here the ``smart constructor'' [branch] instead of [Branch]. *) let branch = function | (_,_,Empty,t) -> t | (_,_,t,Empty) -> t | (p,m,t0,t1) -> Branch (p,m,t0,t1) let rec rmv k = function | Empty -> Empty | Leaf(j,_) as t -> if k == j then Empty else t | Branch (p,m,t0,t1) as t -> if match_prefix k p m then if zero_bit k m then branch (p, m, rmv k t0, t1) else branch (p, m, t0, rmv k t1) else t let remove k t = rmv k t (*s One nice property of Patricia trees is to support a fast union operation (and also fast subset, difference and intersection operations). When merging two branching trees we examine the following four cases: (1) the trees have exactly the same prefix; (2/3) one prefix contains the other one; and (4) the prefixes disagree. In cases (1), (2) and (3) the recursion is immediate; in case (4) the function [join] creates the appropriate branching. *) let rec merge = function | Empty, t -> t | t, Empty -> t | Leaf(k,e), t -> add k e t | t, Leaf(k,e) -> add k e t | (Branch (p,m,s0,s1) as s), (Branch (q,n,t0,t1) as t) -> if m == n && match_prefix q p m then (* The trees have the same prefix. Merge the subtrees. *) Branch (p, m, merge (s0,t0), merge (s1,t1)) else if m < n && match_prefix q p m then (* [q] contains [p]. Merge [t] with a subtree of [s]. *) if zero_bit q m then Branch (p, m, merge (s0,t), s1) else Branch (p, m, s0, merge (s1,t)) else if m > n && match_prefix p q n then (* [p] contains [q]. Merge [s] with a subtree of [t]. *) if zero_bit p n then Branch (q, n, merge (s,t0), t1) else Branch (q, n, t0, merge (s,t1)) else (* The prefixes disagree. *) join (p, s, q, t) let union s t = merge (s,t) (*s When checking if [s1] is a subset of [s2] only two of the above four cases are relevant: when the prefixes are the same and when the prefix of [s1] contains the one of [s2], and then the recursion is obvious. In the other two cases, the result is [false]. *) let rec subset s1 s2 = match (s1,s2) with | Empty, _ -> true | _, Empty -> false | Leaf(k1,_), _ -> mem k1 s2 | Branch _, Leaf _ -> false | Branch (p1,m1,l1,r1), Branch (p2,m2,l2,r2) -> if m1 == m2 && p1 == p2 then subset l1 l2 && subset r1 r2 else if m1 > m2 && match_prefix p1 p2 m2 then if zero_bit p1 m2 then subset l1 l2 && subset r1 l2 else subset l1 r2 && subset r1 r2 else false (*s To compute the intersection and the difference of two sets, we still examine the same four cases as in [merge]. The recursion is then obvious. *) let rec inter s1 s2 = match (s1,s2) with | Empty, _ -> Empty | _, Empty -> Empty | Leaf(k1,_), _ -> if mem k1 s2 then s1 else Empty | _, Leaf(k2,_) -> if mem k2 s1 then s2 else Empty | Branch (p1,m1,l1,r1), Branch (p2,m2,l2,r2) -> if m1 == m2 && p1 == p2 then merge (inter l1 l2, inter r1 r2) else if m1 < m2 && match_prefix p2 p1 m1 then inter (if zero_bit p2 m1 then l1 else r1) s2 else if m1 > m2 && match_prefix p1 p2 m2 then inter s1 (if zero_bit p1 m2 then l2 else r2) else Empty let rec diff s1 s2 = match (s1,s2) with | Empty, _ -> Empty | _, Empty -> s1 | Leaf(k1,_), _ -> if mem k1 s2 then Empty else s1 | _, Leaf(k2,_) -> remove k2 s1 | Branch (p1,m1,l1,r1), Branch (p2,m2,l2,r2) -> if m1 == m2 && p1 == p2 then merge (diff l1 l2, diff r1 r2) else if m1 < m2 && match_prefix p2 p1 m1 then if zero_bit p2 m1 then merge (diff l1 s2, r1) else merge (l1, diff r1 s2) else if m1 > m2 && match_prefix p1 p2 m2 then if zero_bit p1 m2 then diff s1 l2 else diff s1 r2 else s1 (*s All the following operations ([cardinal], [iter], [fold], [for_all], [exists], [filter], [partition], [choose], [elements]) are implemented as for any other kind of binary trees. *) let rec cardinal = function | Empty -> 0 | Leaf _ -> 1 | Branch (_,_,t0,t1) -> cardinal t0 + cardinal t1 ;; let rec iter f = function | Empty -> () | Leaf(_,e) -> f e | Branch (_,_,t0,t1) -> iter f t0; iter f t1 ;; let rec fold f s accu = match s with | Empty -> accu | Leaf(_,e) -> f e accu | Branch (_,_,t0,t1) -> fold f t0 (fold f t1 accu) ;; let rec for_all p = function | Empty -> true | Leaf(_,e) -> p e | Branch (_,_,t0,t1) -> for_all p t0 && for_all p t1 ;; let rec exists p = function | Empty -> false | Leaf(_,e) -> p e | Branch (_,_,t0,t1) -> exists p t0 || exists p t1 ;; let filter p s = let rec filt acc = function | Empty -> acc | Leaf(k,e) -> if p e then add k e acc else acc | Branch (_,_,t0,t1) -> filt (filt acc t0) t1 in filt Empty s ;; let partition p s = let rec part (t,f as acc) = function | Empty -> acc | Leaf(k,e) -> if p e then (add k e t, f) else (t, add k e f) | Branch (_,_,t0,t1) -> part (part acc t0) t1 in part (Empty, Empty) s ;; let rec choose = function | Empty -> raise Not_found | Leaf(_,e) -> e | Branch (_, _,t0,_) -> choose t0 (* we know that [t0] is non-empty *) ;; let elements s = let rec elements_aux acc = function | Empty -> acc | Leaf(_,e) -> e :: acc | Branch (_,_,l,r) -> elements_aux (elements_aux acc l) r in elements_aux [] s ;; (*s Another nice property of Patricia trees is to be independent of the order of insertion. As a consequence, two Patricia trees have the same elements if and only if they are structurally equal. *) let equal = (=) let compare = compare (*s Additional functions w.r.t to [Set.S]. *) let rec intersect s1 s2 = match (s1,s2) with | Empty, _ -> false | _, Empty -> false | Leaf(k1,_), _ -> mem k1 s2 | _, Leaf(k2,_) -> mem k2 s1 | Branch (p1,m1,l1,r1), Branch (p2,m2,l2,r2) -> if m1 == m2 && p1 == p2 then intersect l1 l2 || intersect r1 r2 else if m1 < m2 && match_prefix p2 p1 m1 then intersect (if zero_bit p2 m1 then l1 else r1) s2 else if m1 > m2 && match_prefix p1 p2 m2 then intersect s1 (if zero_bit p1 m2 then l2 else r2) else false [-- Attachment #4: foo.mli --] [-- Type: application/octet-stream, Size: 326 bytes --] type foo;; type foo_node = | Integer of int | String of string | Set of foo Inttagset.t type foo_set = foo Inttagset.t val foo_node : foo -> foo_node;; val foo_int : int -> foo val foo_string : string -> foo val foo_set : foo_set -> foo val foo_add : foo -> foo_set -> foo_set val foo_mem : foo -> foo_set -> bool [-- Attachment #5: foo.ml --] [-- Type: application/octet-stream, Size: 595 bytes --] type foo = { foo_tag : int; foo_val : foo_node } and foo_node = | Integer of int | String of string | Set of foo Inttagset.t type foo_set = foo Inttagset.t;; let foo_node f = f.foo_val let tag_counter = ref 0 let foo_int i = incr tag_counter; { foo_tag = !tag_counter; foo_val = Integer i } let foo_string s = incr tag_counter; { foo_tag = !tag_counter; foo_val = String s } let foo_set s = incr tag_counter; { foo_tag = !tag_counter; foo_val = Set s } let foo_add f s = Inttagset.add f.foo_tag f s;; let foo_mem f s = Inttagset.mem f.foo_tag s;; [-- Attachment #6: test.ml --] [-- Type: application/octet-stream, Size: 433 bytes --] #load "inttagset.cmo";; #load "foo.cmo";; open Foo;; let v1 = foo_set (foo_add (foo_int 4) (foo_add (foo_string "hello") Inttagset.empty));; let v2 = foo_set (foo_add (foo_string "world") (foo_add v1 Inttagset.empty));; let rec all_strings foo acc = match foo_node foo with | Integer _ -> acc | String s -> s::acc | Set s -> Inttagset.fold all_strings s acc ;; all_string v2;; ^ permalink raw reply [flat|nested] 5+ messages in thread
end of thread, other threads:[~2003-03-26 15:59 UTC | newest] Thread overview: 5+ messages (download: mbox.gz / follow: Atom feed) -- links below jump to the message on this page -- 2003-03-26 6:28 [Caml-list] Recursive types and functors David Brown 2003-03-26 8:25 ` Jean-Christophe Filliatre 2003-03-26 8:57 ` David Brown 2003-03-26 15:59 ` brogoff 2003-03-26 9:13 ` Claude Marche
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