* [Caml-list] OCaml error message
@ 2004-05-03 18:19 Holger Schulz
2004-05-03 18:38 ` Jean-Baptiste Rouquier
2004-05-03 18:42 ` Matt Gushee
0 siblings, 2 replies; 4+ messages in thread
From: Holger Schulz @ 2004-05-03 18:19 UTC (permalink / raw)
To: caml-list
I've following declarations
---cut---
type rat = int * int;;
exception Denominator_Zero;;
let rec ggT : (int * int) -> int = fun (x,y) -> if y = 0 then x else ggT
(y, x mod y)
let kgV : int * int -> int = fun (x,y) -> (x / ggT (x,y)) * y
let kuerze : rat -> rat = function (m,n) -> if n = 0 then raise
Denominator_Zero
else let g=ggT (m,n) in (m div g,n div g)
---cut---
Loading it with #use give the following error message, which I do not
understand. Could anyone help me?
---cut--
# #use "B2A3.ml";;
type rat = int * int
exception Denominator_Zero
val ggT : int * int -> int = <fun>
val kgV : int * int -> int = <fun>
File "B2A3.ml", line 10, characters 29-30:
This expression is not a function, it cannot be applied
---cut---
Thanks
hs
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^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: [Caml-list] OCaml error message
2004-05-03 18:19 [Caml-list] OCaml error message Holger Schulz
@ 2004-05-03 18:38 ` Jean-Baptiste Rouquier
2004-05-03 18:42 ` Matt Gushee
1 sibling, 0 replies; 4+ messages in thread
From: Jean-Baptiste Rouquier @ 2004-05-03 18:38 UTC (permalink / raw)
To: Holger Schulz; +Cc: caml-list
Replace "div" with "/".
By the way, you don't need to write the types of the functions : just write
let rec ggT (x,y) =
if y = 0 then x
else ggT (y, x mod y)
and rely on type inference.
There is also a beginer's list :
http://groups.yahoo.com/group/ocaml_beginners/.
Regards,
Jean-Baptiste Rouquier
http://perso.ens-lyon.fr/jean-baptiste.rouquier
>---cut---
>type rat = int * int;;
>
>exception Denominator_Zero;;
>
>let rec ggT : (int * int) -> int = fun (x,y) -> if y = 0 then x else ggT
>(y, x mod y)
>
>let kgV : int * int -> int = fun (x,y) -> (x / ggT (x,y)) * y
>
>let kuerze : rat -> rat = function (m,n) -> if n = 0 then raise
>Denominator_Zero
> else let g=ggT (m,n) in (m div g,n div g)
>---cut---
>
>Loading it with #use give the following error message, which I do not
>understand. Could anyone help me?
>
>---cut--
># #use "B2A3.ml";;
>type rat = int * int
>exception Denominator_Zero
>val ggT : int * int -> int = <fun>
>val kgV : int * int -> int = <fun>
>File "B2A3.ml", line 10, characters 29-30:
>This expression is not a function, it cannot be applied
>---cut---
>
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^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: [Caml-list] OCaml error message
2004-05-03 18:19 [Caml-list] OCaml error message Holger Schulz
2004-05-03 18:38 ` Jean-Baptiste Rouquier
@ 2004-05-03 18:42 ` Matt Gushee
1 sibling, 0 replies; 4+ messages in thread
From: Matt Gushee @ 2004-05-03 18:42 UTC (permalink / raw)
To: caml-list
On Mon, May 03, 2004 at 08:19:19PM +0200, Holger Schulz wrote:
> I've following declarations
>
> ---cut---
> type rat = int * int;;
>
> exception Denominator_Zero;;
>
> let rec ggT : (int * int) -> int = fun (x,y) -> if y = 0 then x else ggT
> (y, x mod y)
>
> let kgV : int * int -> int = fun (x,y) -> (x / ggT (x,y)) * y
>
> let kuerze : rat -> rat = function (m,n) -> if n = 0 then raise
> Denominator_Zero
> else let g=ggT (m,n) in (m div g,n div g)
> ---cut---
>
> Loading it with #use give the following error message, which I do not
> understand. Could anyone help me?
> This expression is not a function, it cannot be applied
Sure. Syntactically speaking, the expression 'm div g' appears to be a
call to function 'm' with arguments 'div' and 'g'. Of course, this
doesn't work because 'm' is an integer.
But actually I think your confusion is elsewhere. It looks like you were
trying to use 'div' as a binary operator; as far as I know, there is no
such operator. Try 'm / g' instead.
By the way, when you get error messages like this, it is helpful to pay
close attention to the *exact* position of the error--e.g., in this
case, the message gave a range of characters pointing to 'm' (and maybe
that character was underlined in the toplevel, too), so you know that
the toplevel or compiler expected 'm' to be a function.
--
Matt Gushee When a nation follows the Way,
Englewood, Colorado, USA Horses bear manure through
mgushee@havenrock.com its fields;
http://www.havenrock.com/ When a nation ignores the Way,
Horses bear soldiers through
its streets.
--Lao Tzu (Peter Merel, trans.)
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^ permalink raw reply [flat|nested] 4+ messages in thread
* [Caml-list] OCaml error message
@ 2004-05-03 18:19 Holger Schulz
0 siblings, 0 replies; 4+ messages in thread
From: Holger Schulz @ 2004-05-03 18:19 UTC (permalink / raw)
To: caml-list
I've following declarations
---cut---
type rat = int * int;;
exception Denominator_Zero;;
let rec ggT : (int * int) -> int = fun (x,y) -> if y = 0 then x else ggT
(y, x mod y)
let kgV : int * int -> int = fun (x,y) -> (x / ggT (x,y)) * y
let kuerze : rat -> rat = function (m,n) -> if n = 0 then raise
Denominator_Zero
else let g=ggT (m,n) in (m div g,n div g)
---cut---
Loading it with #use give the following error message, which I do not
understand. Could anyone help me?
---cut--
# #use "B2A3.ml";;
type rat = int * int
exception Denominator_Zero
val ggT : int * int -> int = <fun>
val kgV : int * int -> int = <fun>
File "B2A3.ml", line 10, characters 29-30:
This expression is not a function, it cannot be applied
---cut---
Thanks
hs
--
"Sie haben neue Mails!" - Die GMX Toolbar informiert Sie beim Surfen!
Jetzt aktivieren unter http://www.gmx.net/info
-------------------
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Bug reports: http://caml.inria.fr/bin/caml-bugs FAQ: http://caml.inria.fr/FAQ/
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^ permalink raw reply [flat|nested] 4+ messages in thread
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2004-05-03 18:19 Holger Schulz
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